5x-20=x^2-5x+5

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Solution for 5x-20=x^2-5x+5 equation: 



5x-20=x^2-5x+5

We move all terms to the left:

5x-20-(x^2-5x+5)=0

We get rid of parentheses

-x^2+5x+5x-5-20=0

We add all the numbers together, and all the variables

-1x^2+10x-25=0

a = -1; b = 10; c = -25;
Δ = b2-4ac
Δ = 102-4·(-1)·(-25)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-10}{-2}=+5$

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